Amplifier

transistor circuits

Darlington pair

Resistance of the LDR and the resisitor should be similar so that there isn't a massive voltage difference.

Bigger the resisitance the less steep the line on a graph I/V

Parallel circuit

The voltmeter showed 6 volts which was the same number of volts as the battery pack. This proves that the voltage is the same anywhere on a parallel circuit.

I1 = Vin/Rtot 

18/09/13 Formula

P = VI     Unit [j/s]

P = E/T

V = E/Q  Unit [V or j/c] 

I = Q/T Unit [c/s or A]

1/Rtot = 1/R1 + 1/R2 + ...


P - Power (unit W)

V- Volts

E - Energy

I - Current  (unit A)

Q - Coulons (unit C) 

J - Joules

T - Time (unit s for seconds)

When you add things in parallel, the resistance lowers and the current increases. 

 

 

1) Resistance = 475 kilo ohms

     Current = 0.0955 A

     Total Volts = 6V

     Volt = 3.50 V

 

     Power = 3.50V* 0.0955A = 0.33425W

 

2) Resistance = 442 ohms

    Current = 0.114 A

    Total Volt = 6V

     Volt = 3.52 V

 

Power = 3.52V * 0.114A = 0.40228W